Ravi Bhatia


 ----jGRASP exec: java demoExceptionsHandling


This program reads integer numbers fom a file. Enter a file name:
junk.txt
You have entered: junk.txt
File not found. Try using 'numbers.txt' file

This program reads integer numbers fom a file. Enter a file name:
numbers.txt
You have entered: numbers.txt
array element number 0 is:45.1
array element number 1 is:56.2
array element number 2 is:65.3
array element number 3 is:76.4
array element number 4 is:87.5
The array index has gone out of bounds. The array has been defined with 5 elements only, but the text file has more numbers
Increase the array index to read file again. Enter new index value: 
3
The index is: 3

This program reads integer numbers fom a file. Enter a file name:
numbers.txt
You have entered: numbers.txt
array element number 0 is:45.1
array element number 1 is:56.2
array element number 2 is:65.3
The array index has gone out of bounds. The array has been defined with 5 elements only, but the text file has more numbers
Increase the array index to read file again. Enter new index value: 
7
The index is: 7

This program reads integer numbers fom a file. Enter a file name:
junk.txt
You have entered: junk.txt
File not found. Try using 'numbers.txt' file

This program reads integer numbers fom a file. Enter a file name:
numbers.tt
You have entered: numbers.tt
File not found. Try using 'numbers.txt' file

This program reads integer numbers fom a file. Enter a file name:
numbers.txt
You have entered: numbers.txt
array element number 0 is:45.1
array element number 1 is:56.2
array element number 2 is:65.3
array element number 3 is:76.4
array element number 4 is:87.5
array element number 5 is:98.0


Now, enter an integer: 
8
You have entered the integer: 8.To see a demo of 'InputMismatchException, run again and enter a floating number



This demo will ask for a number and divide the number by integers from 5 to 0. Please enter a number:
4
You have entered the number: 4.0

 ----jGRASP: operation complete.