/**

* This is the example I was writing in class when we ran out of time

* Note that if you reverse the order of the catch blocks this WILL

* compile. Note also that in line 11 we had to declare str a String

* not a char because Integer.parseInt works on Strings.

*

* @author Elizabeth Adams

* date September 2, 2008

*/

import java.util.*;

public class TE

{

public static void main (String [] args)

{

String str;

int number;

str = "5";

try

{

number = Integer.parseInt(str);

} // end try

catch (IllegalArgumentException ile)

{

System.out.println("Bad number format.");

System.out.println (ile.getMessage());

ile.printStackTrace();

} // end catch ile

// the following statement will cause a COMPILE error because

// a NumberFormatException can be caught by IllegalArgumentException

// which is above it in the hierarchy (is a super class)

// The error is shown after the catch block

catch (NumberFormatException nfe)

{

System.out.println(str + " is not a number.");

System.out.println (nfe.getMessage());

nfe.printStackTrace();

} //end catch nfe

// TE.java:21: exception java.lang.NumberFormatException has already been caught

// catch (NumberFormatException nfe)

// ^

// 1 error

} // end main

} // end class