HW #19 KEY
Due November 30, 2005
Name __________________________
Given the binary mantissa below where the binary point is
assumed to be at the left of the mantissa answer the following questions
- Show
where the binary point is if the mantissa is multiplied by 22 10.11001101
- What
is its base 10 value?
answer b is 2.8007812500E+00
- Show
where the binary point is if the mantissa is multiplied by 23 101.1001101
- What
is its base 10 value? answer d is
5.6015625000E+00
- Show where the binary point is if the mantissa is
multiplied by 21 1.011001101
- What is its base 10 value? answer f is 1.4003906250000000000000000E+00
- Show
where the binary point is if the mantissa is multiplied by 81
101.1001101
- What is its base 10 value? answer h is 5.6015625000E+00
- Show
where the binary point is if the mantissa is multiplied by 83 101100110.1
- What is its base 10 value? answer
j is 3.5850000000E+02
- Show
where the binary point is if the mantissa is multiplied by 82 101100.1101
- What
is its base 10 value? answer l is
1.0940551758E-02
- Show
where the binary point is if the mantissa is multiplied by 161 1011.001101
- What
is its base 10 value? answer n is
1.1203125000E+01
- Show
where the binary point is if the mantissa is multiplied by 162 10110011.01
- What
is its base 10 value?
answer p is 1.7925000000E+02
- Show
where the binary point is if the mantissa is multiplied by 163 101100110100.
- What
is its base 10 value? answer r is
2.8680000000E+03
For each of the following pairs of numbers in twos
complement form
i.
add them together
ii.
tell whether you are really adding or
subtracting
iii.
tell what the base 10 value of the result is
iv.
tell whether there is overflow or not
a.
010101012 =8510 b. 110011002 = -5210 c. 110101102
= -4210
001101102 =5410
011001102 =10210
101011102 = -8210
i 100010112
001100102 100001002
ii adding subtracting adding
iii -11710 5010 -12410
iv overflow no
overflow no overflow